(v^2-3v-4)/(4v^2-4)

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Solution for (v^2-3v-4)/(4v^2-4) equation: 


D( v )

4*v^2-4 = 0

4*v^2-4 = 0

4*v^2-4 = 0

4*v^2 = 4 // : 4

v^2 = 1

v^2 = 1 // ^ 1/2

abs(v) = 1

v = 1 or v = -1

v in (-oo:-1) U (-1:1) U (1:+oo)

(v^2-(3*v)-4)/(4*v^2-4) = 0

(v^2-3*v-4)/(4*v^2-4) = 0

v^2-3*v-4 = 0

v^2-3*v-4 = 0

DELTA = (-3)^2-(-4*1*4)

DELTA = 25

DELTA > 0

v = (25^(1/2)+3)/(1*2) or v = (3-25^(1/2))/(1*2)

v = 4 or v = -1

(v+1)*(v-4) = 0

((v+1)*(v-4))/(4*v^2-4) = 0

( v+1 )

v+1 = 0 // - 1

v = -1

( v-4 )

v-4 = 0 // + 4

v = 4

v in { -1} 

v = 4

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